Q PLC

[Rodney 21]

I am presently working on a Q series P.L.C and in the Ladder code there is bit addressing e.g D1001.0. I have found that if D1001 is between 0 and 3 then d1001.0 is on. However I also have D1001.1 and I can not find what values turn D1001.1 on. Any help would be appriciated. Rodney

[Veganic 8]

D100 = Word = 16 bits = 0000000000000010 for example. D100.0 = first bit of D100 = 0 in the case above. D100.1= 2nd bit = 1 in the case above up to D100.F if D1001 = 1 base 10 then D1001 = 01 binary. Therefore D1001.0 = 1 and D1001.1 = 0. if D1001 = 2 base 10 then D1001 = 10 binary. Therefore D1001.0 = 0 and D1001.1 = 1. if D1001 = 3 base 10 then D1001 = 11 binary. Therefore D1001.0 = 1 and D1001.1 = 1. Edit:I'm in Staffordshire, so PM me if you need anything! Edited 2 Feb 2010 by Veganic