Copy INT into second half of a DINT

[BennieC 0]

Hi all, 

I'm trying to copy an INT into bits 16 to 31 of a DINT for a VSD speed control. It sounds easy in theory, but I'm struggling to find a practical solution.

Is there a straight forward way of achieving this? I'm using Logix Designer

Thanks

Edited 17 Oct 2017 by BennieC

[Michael Lloyd 85]

There is a command for that in CLX but you didn't mention which PLC you are using.

BTD - Bit Field Distribute

Page 384

http://literature.rockwellautomation.com/idc/groups/literature/documents/rm/1756-rm003_-en-p.pdf

[Joe E. 259]

Also look at the COP instruction. If you set up your INT as one INT in an array of 2 INTs with the other INT being whatever needs to be in the lower word of the DINT.  You then COP the array into the DINT using a length of 1.

Alternatively, you can MUL the INT by 2^16 (to shift the bits 16 places to the left) into a holding DINT tag and then MVM (masked move) the holding DINT into the destination DINT.

It looks like the BTD instruction will be the cleanest option, though.

[jimtech67 2]

Multiply your integer by 65536 with the destination being the double integer (or Long)

[BennieC 0]

Thanks for the replies, I'll give it a go after I've sorted the next problem I've found with the setup of addressing using RSNetWorx.