plcman

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Posts posted by plcman

  1. Posted

    Hi

     

    I have an old F1 PLC I need to reprogram. I am using MEDOC to do this.

    Can anybody remember the keystrokes I need to add a number to a data register. i.e. [ADD D0 K1 D0]

    I got as far as pressing '8' but everything I then type gives me the message invalid instruction.

     

    Any help gratefully received.

  2. Posted

    Hi

    Could anybody tell me if the C500/C120 support tool in CX Programmer uploads the I/O table when it uploads the program from a C500.

    I have already backed up a program from a C500 using SYSWIN but SYSWIN doesn't allow me to edit, create or generate an I/O table, so when the program is downloaded to a sister machine, I get I/O errors that can't be cleared.

    Any help grateully received

  5. Posted

    Hi I am trying to do a simple mod to a project on a factorytalk view me system. I got the packaged file from the developer and opened it up into FT view studio, it opens fine, I add a tag and a numeric item to a screen then turn it into a .mer file and load it into the versview plus 1000. I get various comms errors so I assume that the packaged file I got from the developer wasn't upto date. So next I upload the working .mer file from the screen, use the application manager to turn it back into an editable file, again do the 1 tag mod, turn it back into a .mer and load it onto the screen and I get errors at startup on a blue banner. a sample of the errors are ! write 1 to PV\Pagenum ! write 45 to {PVSys_seconde} ! write 2 to {PVSys_minute} !unable to open display If I clear these and go onto the hmi screens, it appears that I am able to operate it ok writing and reading from the PLC. It seems very weird that adding a single tag can do this. My problem is that I only have a couple of hours between shifts at this place to get it going else I have to revert to the original program for production. Any help or anybody elses experience would be gratefully received.

  8. Posted

    Hi I am trying to add a 1794-0e4 module to an existing rack. The plc is a PLC5 l40 enhanced jobby. The rack (rack3) originally consisted of a 1794-ASB and 6off 1794-OV16, the I/O configuration on rack 3 was set to 3/4 and I changed this to full. The 1794-oe4 is in 7th position (slot6) I am using BTR and BTW to setup and read from the module, I have them setup as Rack 3, Group 6, Module 0. The reads and writes go through OK no errors, but I don't get any output from the module. My control block is N17:0 and is set to zero. My data block N18:0, N18:0 - 3 are my analog values, N18:5 setsup the module as 4-20mA so bits 8 - 11 are set to 1. I would appreciate help from anybody who can see where I am going wrong. Many Thanks Al

  9. Posted

    Hi Can anybpdy tell me the difference between the AY13E and AY13EU modules on a A3N CPU system. I know that they are both 32 point relay output modules but wondered if they are interchangeable. Many Thanks for any advice.

  11. Posted

    Thanks BobB The job I have had the enquiry about is obviously an old installation, would it have been the norm' to install any of these items in the original installation or are they all items that the programmer would have taken away? Many thanks for all your advice!

  13. Posted

    Hi Thanks for that, I already looked through all of that but could find very little info specific to c1000h, I don't want to turn up on site ill-equipped. So any specific info would be v.helpful

  17. Posted

    Hi Take a look at the Control Techniques Unidrive SP solutions platform. These inverters can work in open loop, vector mode and in servo mode, more importantly they have programmable plug in application modules which allow you to control the logic and motion from one piece of kit with no analogue I/O etc. Also when more than one axis is required they can be linked over various field bus options. Regards Alan Edwards www.wolfautomation.co.uk

  18. Posted

    Hi What are you pressing and what pressure due you need to press it? My experience is with High speed piercing and shearing and a PID loop in a PLC certainly would not be fast enough. More information about your application may be useful. Regards Alan Edwards www.wolfautomation.co.uk

  19. Posted

    Hi This works on my app Private Function fHRSendBCD(RegVal As Long, Reg As Integer) As Integer Dim iLow As Long Dim iHigh As Long Dim iString As String iString = CStr(RegVal) If Len(iString) > 4 Then iHigh = Val(Left(iString, Len(iString) - 4)) Else iHigh = 0 End If If Len(iString) < 5 Then iLow = Val(iString) Else iLow = Val(Right(iString, 4)) End If plcOmron.HR(Reg) = CLng("&h" & iLow) plcOmron.HR(Reg + 1) = CLng("&h" & iHigh) End Function Where plcOmron is the name of the object. Hope this helps Regards Alan Edwards http://www.wolfelectrical.co.uk

  24. Posted

    I already answered this on another forum, the link to the cable schematic is below SC09 Schematic As for the cable that does not need 5v from the PLC try looking here alternate sc09 plcman www.wolfelectrical.co.uk