Posted 8 Nov 2019 (edited) Hi new to the forum, and first post, however, I have found an abundance of great information here, so I was hoping someone might able to help me with an issue. PLC is BRX BX-DME1-10ED13-D I am trying to read an analog output from a sensor that is capable of essentially outputting a mA signal proportional to where a printed line, or contrasting edge is at in its field of view. It is used for web guiding applications to make sure the web is tracking straight, so you can identify if the line or edge is moving to one direction or the other, and correct the web with an articulating web guide. I have attached the diagram for the sensor, but I cannot for the life of me figure out 2 things 1) The power supply to the sensor is listed as follows Supply current - From fife control +/- 12vdc 50ma (+)12vdc AND - 40ma (- )12vdc how do you provide both (+) and( -) 12VDC for the supply power to a sensor- 2 power supplies with the the opposite polarities grounded on each? 2) The outputs are listed as "Sum" and "Differential" so apparently there are two outputs, i dont know if anyone has come across these terms relative to sensors before, but I am trying to sort these out. According to the OEM Sensor Output Range -20 mA to +20 mA for line guiding -20 mA to +10 mA for edge Guiding I have attached the pin out diagram as well as the sensor spec sheet, but I am curious to see if anyone might have insight as to how I would get an analog input reading from this configuration? Thank you in advance for any help! 224615.pdf SE-26B Product Sheet.pdf Edited 8 Nov 2019 by Scott3229 Share this post Link to post Share on other sites
Posted 10 Nov 2019 According to the installation manual, this unit is connected to a controller that provides the +/- voltage supply. You need to look at the controller manual to see what kind of input or output it provides. Mike Fife_SE-26B_Manual.pdf Share this post Link to post Share on other sites
