BennieC

Copy INT into second half of a DINT

5 posts in this topic

Hi all, 

I'm trying to copy an INT into bits 16 to 31 of a DINT for a VSD speed control. It sounds easy in theory, but I'm struggling to find a practical solution.

Is there a straight forward way of achieving this? I'm using Logix Designer

Thanks

Edited by BennieC

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Also look at the COP instruction. If you set up your INT as one INT in an array of 2 INTs with the other INT being whatever needs to be in the lower word of the DINT.  You then COP the array into the DINT using a length of 1.

Alternatively, you can MUL the INT by 2^16 (to shift the bits 16 places to the left) into a holding DINT tag and then MVM (masked move) the holding DINT into the destination DINT.

It looks like the BTD instruction will be the cleanest option, though.

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Multiply your integer by 65536 with the destination being the double integer (or Long)

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Thanks for the replies, I'll give it a go after I've sorted the next problem I've found with the setup of addressing using RSNetWorx. 

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